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If $f$ is continuous function of $[0,1]$ then $f$ is bounded and $\lim_{x\rightarrow x_0}f(x)= f(x_0)$
If $f$ is continuous function of $[0,1]$ then $f$ is bounded and $\lim_{x\rightarrow x_0}f(x)= f(x_0)$
If $f$ is continuous function of $[0,1]$ then $f$ is bounded and $\lim_{x\rightarrow x_0}f(x)= f(x_0)$
My approach :
We can write
$$
\begin{align*}
\int_{[0,1]}f(t)dt&\leq \sup(f) \int_{[0,1]}\min\{f(t),\sup(f)\}dt\\
&=\sup(f) \int_{[0,1]}\min\{f(t),\sup(f)\}dt\\
&=\sup(f) \int_{[0,1]}f(t)dt
\end{align*}
$$
We know that if $f$ is continuous on $[0,1]$ then $f$ is bounded. I am stuck here. Please help.
A:
(1) If $f$ is continuous then $f(t)\geq f(0)$ for each $t\in [0,1]$ and $f(
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